Did some figuring on this...
I have an old heater from a B30. The heating wire itself is good, but the aluminum terminals have rotted off. The electrical info, from the nameplate reads:
110 volts, 375 watts.
If I = P/V, then the current = 375/110 = 3.41A
If R = V/I, then the resistance = 32.3 ohms (The ACTUAL resistance measures 28.5 ohms, for whatever that's worth)
The number of turns is approx. 34, at 2.5"/turn, which gives a heater ribbon length of 85"
85" = 7.08 ft., 32.3 ohms would require a wire resistance of approx. 4.6 ohms/ft.
I measure the wire ribbon size at .004 thick X .031" wide.
This source has wire available in 5.15 ohms/ft, .0035" thick, and 1/32" wide, which would work:
https://jacobs-online.biz/nichrome_ribbon_wire.htmIt's the first size listed, with various lengths available.
Paula